The density of iron at 25 C is 7.871 g/cm^3
what is the volume of one mole of solid iron at 25 C?
i understand that volume = m/d but how would i go about solving this?
Isn't one mole of iron equal to its atomic mass in grams? Can you look up the atomic mass of iron?
thanks, this is how i calculated it:
1 mol Fe/.141 mol/cm^3 = 7.10 cm^3
(the .141 came from converting the density in to moles)
is that correct?
then the next step in the problem is to find the volume of 1 mol of Fe atoms assuming each atom to be spherical. the atomic radius is 0.126 nm.
so i calculated:
4/3 pi (0.126 nm)^3 = .00838 nm^3
is that correct?
thank you for your help.
To determine the volume of one mole of solid iron at 25°C, you can follow these steps:
1. Find the molar mass of iron (Fe) from the periodic table. The molar mass of iron is approximately 55.85 g/mol.
2. Identify the density of iron at 25°C, which is given as 7.871 g/cm³. This value represents the mass of one cubic centimeter of iron.
3. Use the molar mass and density to calculate the volume.
a. Start with the molar mass of iron (55.85 g/mol).
b. Divide the molar mass by the density. This gives you the volume of iron required for one mole at 25°C.
Volume = Molar mass / Density
Volume = 55.85 g/mol / 7.871 g/cm³
c. The units will cancel out, leaving you with the volume in cubic centimeters (cm³) for one mole of iron.
Keep in mind that the calculated volume will be in cubic centimeters because the density is given in grams per cubic centimeter.