the number of mosquitoes that brown bats can eat in an hour has a mean of 600 and a standard deviation of 200. a study observed a random sample of 80 little brown bats.
hat is the minimum no. of mosquitoes that the upper 25% of little brown bats eat in an hour?
Please.. I need your help...
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion and its related Z score. Insert values into the equation above to find the score (# of mosquitoes).
Sure, I'm here to help! To find the minimum number of mosquitoes that the upper 25% of little brown bats eat in an hour, we can use the concept of z-scores and the standard normal distribution.
Step 1: Convert the problem to a standard normal distribution
The mean of the number of mosquitoes eaten by brown bats is given as 600, and the standard deviation is given as 200. We need to calculate the z-score for the upper 25% of the distribution. The upper 25% corresponds to a z-score of 0.674.
Step 2: Calculate the minimum number of mosquitoes
To find the minimum number of mosquitoes, we can use the formula:
Minimum number of mosquitoes = Mean + (z-score * standard deviation)
Plugging in the values, we have:
Minimum number of mosquitoes = 600 + (0.674 * 200)
Calculating the expression, we get:
Minimum number of mosquitoes ≈ 734.8
Therefore, the minimum number of mosquitoes that the upper 25% of little brown bats eat in an hour is approximately 735.
Note: Keep in mind that this is an approximation since we rounded the final result to a whole number.