A piece of Copper alloy with a mass of 89.0 g is heated at 30.0 degrees C to 50.0 degrees C. In the process, it absorbs 517 J of energy as heat. What is the specific heat of this copper alloy?

and Please do a step by step, I really want to see where I keep going wrong.

If you had posted your work I would have seen where it was and if you were missing a concept. And it would have taken me much less time.

q = mass x specific heat x delta T.
517 = 89.0 x specific heat x 20
Sp. h. = ?
Answer is 0.290 J/g*C

To find the specific heat of the copper alloy, you can use the formula:

q = mcΔT

Where:
q is the amount of heat absorbed
m is the mass of the copper alloy
c is the specific heat of the copper alloy
ΔT is the change in temperature

In this case, you are given:
q = 517 J (amount of heat absorbed)
m = 89.0 g (mass of the copper alloy)
ΔT = 50.0°C - 30.0°C = 20.0°C (change in temperature)

Now, we can plug in the given values into the formula:

517 J = (89.0 g) * c * 20.0°C

To isolate the specific heat, we need to rearrange the formula:

c = q / (m * ΔT)

Now, substitute the given values:

c = 517 J / (89.0 g * 20.0°C)

First, let's convert the mass to kilograms (kg):
89.0 g = 89.0 g / 1000 g/kg = 0.089 kg

Now, substitute the values once again:

c = 517 J / (0.089 kg * 20.0°C)

Now, let's solve the equation step by step:

Step 1: Calculate the product of mass and change in temperature:
(0.089 kg * 20.0°C) = 1.78 kg°C

Step 2: Divide the given amount of heat absorbed by the product obtained in step 1:
517 J / 1.78 kg°C = 290.5 J/(kg°C)

Therefore, the specific heat of the copper alloy is approximately 290.5 J/(kg°C).