Math

How would you find the zeroes for this?
x^2+3x-9

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  1. The zeroes of the function or "roots" are not integers or fractions in this case. Use the quadratic equation.
    The roots are
    [-3 +/- sqrt (9+36)]/2 = -4.854 and 1.854

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  2. can't you partial factor

    x^2+3x+9

    x^2+3x=0
    x(x+3)=0
    x= 0 or x=-3

    what am I doing wrong?

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  3. The equation you wrote was x^2+3x-9, not x^2+3x+9. Neither factors in the manner you have shown. You can't just throw out the 9, as you have done.

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  4. Then when is partial factoring used?

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