What is the net ionic equation for this reaction?
2MnO4 (aq) + 5H2C2O4 (aq) + 6H(aq)----->10CO2 (g) + 2Mn(aq) + 8H2O(l)
If you place the correct charges on the ions you have the net ionic equation.
To determine the net ionic equation for a reaction, we need to first write the balanced molecular equation, followed by the complete ionic equation, and finally the net ionic equation.
1. Write the balanced molecular equation:
2MnO4^- (aq) + 5H2C2O4 (aq) + 6H+ (aq) ---> 10CO2 (g) + 2Mn2+ (aq) + 8H2O (l)
2. Write the complete ionic equation by breaking down all the soluble electrolytes into their constituent ions:
2MnO4^- (aq) + 5H2C2O4 (aq) + 12H+ (aq) ---> 10CO2 (g) + 2Mn2+ (aq) + 8H2O (l)
3. Identify the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction). In this case, the spectator ions are the 12H+ ions.
4. Write the net ionic equation by removing the spectator ions from the complete ionic equation:
2MnO4^- (aq) + 5H2C2O4 (aq) ---> 10CO2 (g) + 2Mn2+ (aq) + 8H2O (l)
Therefore, the net ionic equation for the given reaction is:
2MnO4^- (aq) + 5H2C2O4 (aq) ---> 10CO2 (g) + 2Mn2+ (aq) + 8H2O (l)