how many kilojoules of heat are absorbed when 1.00 L of water is heated from 18C to 85C? density of water is 1.0 g/ml
wait. is it 4.186 J/g*C?
so the answer is 280.462 KJ?
q = mass x specific heat x (Tfinal-Tinitial)
how do u change L to grams?
1.00 L = 1,000 mL.
The density of water is 1.0 g/mL; therefore, 1,000 mL x 1.0 g/mL = 1,000 grams.
thanks.
q=1000g x specific heat x 67C
what is the specific heat?