calc

how to do the integral of
(ln(x))/(x^2)

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  1. Try integration by parts.
    Let u = ln x
    du = dx/x
    dv = 1/x^2 dx
    v = -1/x
    Integral of lnx/x^2 = Integral of udv
    = uv - Integral of vdu
    = -(ln x)/x - Integral of -dx/x^2
    Take it from there, but check my work also

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