Please let me know if I understand this correctly.
Find the slope and the y-intercept of each equation:
1)y-9x= 1/2
+9x= 1/2 + 9x
y= 1/2 + 9x
slope:9; y-intercept: 1/2
2)2y-6=3x
+6 +6
2y=3x + 6
- -
2 2
so then: y=3x+3
3) -2y=6(5-3x)
-2y= 30-18x
- --
-2 -2
so then: y=-15-18x
(slope: -18; y-intercept: -15)
Thank you!!!!!!
1) correct, but the usual form is y=mx+b, so you'd have y=9x + 1/2
2) you forgot do divide 3x by 2. y = 3/2 x + 3
3)You're getting things mixed up. Don't try to rearrange things in your head.
-2y = 30 - 18x
-2y = -18x + 30
y = 9x - 15
Thank you so much - that clears it up for me!!! It's just been awhile since I've done this.
Yes, your understanding is correct. Let me explain how you found the slope and y-intercept for each equation:
1) For the equation "y - 9x = 1/2", you first added 9x to both sides to isolate the variable y. This gave you the equation "y = 1/2 + 9x". You correctly identified that the slope is 9 (the coefficient of x) and the y-intercept is 1/2 (the constant term).
2) In the equation "2y - 6 = 3x", you added 6 to both sides to isolate the variable 2y. This resulted in the equation "2y = 3x + 6". By dividing both sides by 2, you simplified it to "y = 3x + 3". This means the slope is 3 (the coefficient of x) and the y-intercept is 3 (the constant term).
3) The equation "-2y = 6(5 - 3x)" can be simplified by distributing 6 to both terms inside the parentheses, which gives you "-2y = 30 - 18x". Then you divided both sides by -2 to isolate y, resulting in "y = -15 - 18x". Here, the slope is -18 (the coefficient of x) and the y-intercept is -15 (the constant term).
Overall, you correctly determined the slope and y-intercept for each equation by manipulating the equations algebraically to isolate y and identify the coefficient of x and the constant term. Well done!