Jack drives 6.45 km to work and his car gets about 0.0147 km per gram of gasoline. Using the balanced chemical equation (you need to find out this equation by yourself), how many grams of CO2 is produced in this trip to work
Gasoline can be represented by octane C8H18. Its combustion, in the most straight-forward sense is to carbon dioxide and water.
2C8H18 + 25O2 ~> 16CO2 + 18H2O
so, he needs 6.45km / .0147km/g = 438.7755g of gas. That assumes complete combustion, of course.
mole weight is about 12*8 + 18*1 = 114g/mole
438.7755g / 114g/mole = 3.849 moles of gasoline
each mole of gasoline produces 8 moles of CO2, so we end up with 30.791 moles, or 30.791*(12+2*16) = 1354.8g of CO2.
Thank you so much!
which answer is it please? you have 2 possible answers. thanks.
To find out how many grams of CO2 are produced in Jack's trip to work, we need to use the balanced chemical equation for the combustion of gasoline. The balanced chemical equation gives us the stoichiometric relationship between reactants and products.
Since we are given the distance Jack drives (6.45 km) and the fuel efficiency of his car (0.0147 km/g gasoline), we need to convert the distance traveled into the amount of gasoline consumed in grams.
First, we can calculate the amount of gasoline Jack used in this trip:
Gasoline used = Distance / Fuel efficiency = 6.45 km / 0.0147 km/g = 439.46 g
Now, we need the balanced chemical equation for the combustion of gasoline. The balanced equation for the complete combustion of octane (a component of gasoline) is as follows:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
This means that for every 2 moles of octane (C8H18) combusted, 16 moles of carbon dioxide (CO2) are produced.
To calculate the moles of gasoline combusted, we need to convert the mass of gasoline used into moles. The molar mass of octane is needed for this conversion. It is 114.222 g/mol.
Moles of gasoline combusted = Mass of gasoline used / Molar mass of octane
= 439.46 g / 114.222 g/mol
= 3.84602 mol
Now, using the stoichiometry of the balanced chemical equation, we can determine the moles of CO2 produced:
Moles of CO2 produced = Moles of gasoline combusted × (16 moles CO2 / 2 moles C8H18)
= 3.84602 mol × (16 mol CO2 / 2 mol C8H18)
= 30.76816 mol CO2
Finally, we can convert the moles of CO2 produced into grams:
Mass of CO2 produced = Moles of CO2 produced × Molar mass of CO2
= 30.76816 mol × 44.01 g/mol
= 1353.62315 g
Therefore, approximately 1353.62 grams of CO2 are produced in Jack's trip to work when he drives a distance of 6.45 km.