FIND dx/dy for y = x^(2x+1)
first take ln of both sides
lny = ln( x^(2x+1) )
= (2x+1)(lnx)
dy/dx / y = 2lnx + (1/x)(2x+1)
dy/dx = x^(2x+1) (2lnx + (1/x)(2x+1)
Don't know what simplification you need.
lny = ln( x^(2x+1) )
= (2x+1)(lnx)
dy/dx / y = 2lnx + (1/x)(2x+1)
dy/dx = x^(2x+1) (2lnx + (1/x)(2x+1)
Don't know what simplification you need.