Find the product and list the full balanced equation.
CuCl2 + AgNO3 -> ?
CuCl2(aq) + 2AgNO3(aq) ==> 2AgCl(s) + Cu(NO3)2(aq)
To find the product and balance the equation, we need to determine the products of the reaction between CuCl2 (copper(II) chloride) and AgNO3 (silver nitrate).
The reaction between CuCl2 and AgNO3 is a double displacement reaction, also known as a precipitation reaction. In this type of reaction, the positive ions and negative ions of two compounds switch places to form new compounds.
The first step is to identify the chemical formulas of the products. In this case, the product will be formed by the combination of the cation (positive ion) from one reactant and the anion (negative ion) from the other reactant.
For CuCl2, the cation is Cu2+ (copper ion) and the anion is Cl- (chloride ion). For AgNO3, the cation is Ag+ (silver ion) and the anion is NO3- (nitrate ion).
Now, we can swap the cations and anions to form the products:
Cu2+ (from CuCl2) combines with NO3- (from AgNO3) to form Cu(NO3)2 (copper(II) nitrate).
Ag+ (from AgNO3) combines with Cl- (from CuCl2) to form AgCl (silver chloride).
So the full balanced equation for the reaction between CuCl2 and AgNO3 is:
CuCl2 + 2AgNO3 -> Cu(NO3)2 + 2AgCl
Note that the coefficient 2 is used in front of AgNO3 and AgCl to balance the equation, ensuring that the number of atoms on each side of the equation is the same.