I have a question concerning this problem:I just want to make sure my formulas are correct before I do problem

It is a hyperbola equation
(y-4)^2/49 - (x-6)^2/72 = 1
1.It is a vertical hyperbola, correct?
2. the a^2 is 49, correct?
3. the b^2 is 72, correct?
4. I find the foci by a^2 + b^2 = c^2, and when I have the square root of "c^2" it would be ( "h" which is 6 in this case, k which is 4 +-whatever "c" ended up to be, correct?
5.Vertices for vertical hyperbola is (h,k+-a), correct

I forgot one question-in a hyperbola, the "a^2" is always under the first variable, whether it be "x" or "y", correct

1. correct

2. and 3.
I always associate a^2 with the x's
and b^2 with the y's, but that is a personal choice.
It will depend how your text or your instructor chooses.
regarding your comment, ...
what if I simply changed the equation to
(x-6)^2/72 - (y-4)^2 /49 = -1 , (which is the preferred method of writing it)
would you now label a^2 as 72 ?
Can you see the problem ?
That is why associating a^2 with the x's and b^2 with the y's makes so much more sense.

4. c^2 = a^2 + b^2 = 121
c = 11
foci : (6, 15) and (6, -7)
(your formula for a vertical hyperbola is correct)

So if I change the formula to = (-1), then I have to change the a^2 to be under the "x" is that correct?

Thank you for your help

All I did was to multiply each term by -1

I like to have all my conic section equations in standard form, that is ,
my circle, ellipse and hyperbola equations start with the "x" term.
As I said, I associate the a^2 with the x's and the b^2 with the y's.
This saves a lot of confusion.

However, if your instructor wants you to do it otherwise, such as the a's always going with the major axis, then do so.

okay-thank you I got it now

1. Yes, the equation you provided represents a vertical hyperbola. This is because the term with '(y - 4)' is squared, which indicates that the hyperbola is vertically oriented.

2. Yes, 'a^2' refers to the value under the numerator of the y-term, and in this case, it is 49.

3. Yes, 'b^2' refers to the value under the numerator of the x-term, and in this case, it is 72.

4. To find the foci of the hyperbola, you are correct that you can use the equation 'a^2 + b^2 = c^2'. In this equation, 'c' represents the distance from the center of the hyperbola to one of the foci. The formula for the coordinates of the foci for a vertical hyperbola is (h, k ± c). In this case, 'h' is 6 (center x-coordinate), 'k' is 4 (center y-coordinate), and 'c' can be calculated by taking the square root of 'a^2 + b^2'.

So, you are correct in your understanding of how to find the foci. The coordinates of the foci would be (6, 4 ± c).

5. For a vertical hyperbola, the vertices are located at coordinates (h, k ± a). In this case, the center of the hyperbola is at (h, k), which is (6, 4), and 'a' is the square root of 'a^2'. So, the vertices of the hyperbola would be (6, 4 ± √a^2).