how can you solve x^2 - 3x = 0 i was using a formula as:

x^2-7x+10=0
(x-5)(x+2)= 0
x-5=0
x+5 +5 x=5

I was following this formula but got stumped on this question please help.

x (x-3) = 0

x = 0 or x = 3

before looking at your answer i found the answer to be 0 too but like this:

x^2-3x=0
x^2-3x+0=0
(x-0)(x+0)=0
0^2-3(0)=0

was my way right

No, because -0x-0x is not -3x

You missed the x = 3 root entirely.
Please do it my way :)

If you insist on completing the square:

x^2 - 3x = 0

(-3/2)^2 = 9/4
so
x^2 - 3 x + 9/4 = 9/4

(x-3/2)^2 = 9/4 =3/2

x- 3/2 = +/- 3/2

x = 3/2 + 3/2 = 3
pr
x = 3/2 - 3/2 = 0

by the way

x^2-7x+10=0
(x-5)(x+2)= 0
x-5=0
x = 5
OR
x+2 = 0
x = -2

do i always have to mention the ors

If it is a quadratic, in general it has two solutions, so you need to give both.

Sometimes, if the vertex of the parabola is exactly on the x axis, the two roots will be the same. For example:
x^2 -4x + 4 = 0
(x-2)(x-2) = 0
x = 2
or
x = 2

oh, okay, thank you!

To solve the equation x^2 - 3x = 0, you can factorize it to find the values of x that satisfy the equation.

Step 1: Rewrite the equation as x(x - 3) = 0.

Step 2: Apply the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.

Setting each factor equal to zero, we have:

x = 0 (from x = 0)
x - 3 = 0 (from x - 3 = 0)

Step 3: Solve each equation separately for x:

For x = 0, the solution is x = 0.

For x - 3 = 0, add 3 to both sides to isolate x:

x - 3 + 3 = 0 + 3
x = 3

So, the solutions to the equation x^2 - 3x = 0 are x = 0 and x = 3.