I'm sorry the computer jammed on an earlier post and I couldn't do anything-so here is the problem I need asistance with Please check and offer advice-I'm NOT SURE IF I USED CORRECT FORMULAS-thank you
the problem is List the center, vertices, and foci of hyberbola for following equation:
(y-2)^2/36 - (x-8)^2/64 = 1
b=6
a=8
Center(8,2)
Vertices=(h,k+a) (h,k-a)=(h, k+-a)=(8,2+-6)=(8,8) (8,-4)

Foci
This is a verticl hyperbola, correct?
So formula for vertices would be Foci should be c^2 = a^2 + b^2
8^2 + 2^2 = 64+36
c=10
foci=(8,2+-10)
(8,-8)
(8,12)

1. looks good to me.

posted by Steve

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