how would I find points to plot a graph for the function f(x)=ln(4-x)?
You asked the same question a few days ago.
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http://www.jiskha.com/display.cgi?id=1326292271
I'm sorry, started a new job and have put in a lot of hours for training - must have forgotten that you replied.
To find points to plot a graph for the function f(x) = ln(4-x), you can start by choosing a range of values for x and calculating the corresponding y-values using the function. Let's go through the step-by-step process:
1. Determine a range of values for x: Start with a range of x-values that you think would be appropriate for your graph. For example, you might choose x-values from -3 to 4 to capture the behavior of the function.
2. Calculate the corresponding y-values: For each x-value chosen from the range, substitute it into the function f(x) = ln(4-x) and compute the corresponding y-value. For instance, if you choose x = -3, substitute it into the function: f(-3) = ln(4-(-3)). In this case, f(-3) would be undefined since the natural logarithm of a negative number is not defined. However, you can repeat this process for other x-values to find valid points.
3. Plot the points on a graph: Once you have calculated a set of x and y-values, plot the points (x, y) on a coordinate plane. Connect the plotted points to visualize the graph of the function f(x) = ln(4-x). Remember to label the x and y-axes appropriately.
Note: It's worth mentioning that the function ln(4-x) is undefined or not defined for x ≥ 4, as the natural logarithm is not defined for non-positive numbers. Therefore, you would not have any points to plot for x-values greater than or equal to 4.