Question

From the Periodic Table, 1 mole of aluminum weighs 27.0 g.,

Therefore;
If 54.0 g of aluminum are placed into the beaker to react with copper(II) chloride, how many grams of the metal product will be produced?

Answer 1

If the reaction is

3CuCl₂ + 2Al = 2AlCl₃ + 3Cu

looks like you have 3 moles of copper for every 2 moles of aluminum.

You have 2 moles of aluminum.