The area of a regular octagon is 35 cm2. What is the area of a regular octagon with sides six times as long?

so do you times this by 6?

no, the area of similar figures is proportional to the square of their sides.

So....
V/35 = (6x)^2/x^2 = 36/1
V = 35(36)
= 1260 cm^2

I don't know what June is talking about, but the person above, reiny, is correct. You would not do that times six, because it's each individual side times six. V/35=6x squared/xsquared = 36/1

so 35*36=1260 cmsquared

Hope that makes sense. Sorry, I don't know why this whole response was so essay-like.

- Doggo

56

To find the area of a regular octagon with sides six times as long, you need to determine the ratio between the areas of the two octagons. Since the length of the sides has been multiplied by 6, the ratio of the areas will be the square of this multiplication (6^2 = 36).

To find the area of the new octagon, you multiply the area of the original octagon by this ratio. Given that the area of the original octagon is 35 cm^2:

Area of new octagon = Area of original octagon × Ratio of areas
= 35 cm^2 × 36
= 1260 cm^2

So, the area of the new octagon with sides six times as long is 1260 cm^2.