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If we add 25g oe calcium carbonat with 73g of Hcl.what is the volume carbon dixiode in litres.
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If we add 25g oe calcium carbonat with 73g of Hcl.what is the volume carbon dixiode in litres.
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Calcium carbonate reacts with HCl according to the following equation:
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CALCULATE THE VOLUME OFHYDROGEN WHEN 25G OF ZINC ADDED TO HCL AT 31`C&778MMHG PRESSURE H=1,ZN=65,CL=35.5,<MOLAR VOLUME OF GAS AT
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Zn +2 HCl >>>H2+ ZnCl2 so for every mole of zinc, one gets one mole of hydrogen gas. you have 25/65
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To calculate the amount of carbon dioxide (CO2) liberated by heating 25 grams of calcium carbonate
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OK I just need help with two final problems that I am stuck on:
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