A stream of water from the nozzle of a fire hoZe emerges horizontally with a speed 16m/s. the nozzle is 20m above the ground, find the time ot hits the groun
s = 1/2 at^2
20 = 1/2 * 9.8 t^2
solve for t
the horizontal velocity makes no difference. It will just affect how far the water goes.
knowing t,
horizontal distance = 16 * t
To find the time it takes for the stream of water to hit the ground, we can use the equations of motion. In this case, we will use the equation for vertical motion.
Assuming there is no air resistance, the only force acting on the stream of water is gravity.
We can use the following equation to calculate the time it takes for an object to fall vertically:
d = (1/2) * g * t^2
Where d is the distance in meters, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time in seconds. In this case, the distance the water travels vertically is 20 meters (the height of the nozzle).
Substituting the known values into the equation, we have:
20 = (1/2) * 9.8 * t^2
To simplify, we can multiply both sides of the equation by 2:
40 = 9.8 * t^2
Next, we divide both sides of the equation by 9.8:
t^2 = 40 / 9.8
t^2 ≈ 4.0816
To solve for t, we take the square root of both sides:
t ≈ √4.0816
t ≈ 2.02 seconds
Therefore, it takes approximately 2.02 seconds for the stream of water to hit the ground.