A drag racer starts her car from rest and accelerates at 9.0 m/s2for the entire distance of 105.0 m. What is its speed at the end of the run? Answer in units of m/s.

v = 9.0 t

d = (1/2) a t^2
105 = 4.5 t^2
t = 4.83 seconds

v = 9 * 4.8 = 43.4 m/s

To find the speed of the drag racer at the end of the run, we can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v = final velocity (unknown)
u = initial velocity (0 m/s, since the car starts from rest)
a = acceleration (9.0 m/s^2)
s = distance traveled (105.0 m)

First, we substitute the known values into the equation:

v^2 = 0^2 + 2 * 9.0 * 105.0

Simplifying:

v^2 = 0 + 1890

v^2 = 1890

Taking the square root of both sides to solve for v:

v = √1890
v ≈ 43.5 m/s

Therefore, the speed of the drag racer at the end of the run is approximately 43.5 m/s.