precalculus

solve the logarithm equation show work.

log_7(x-8)- log_7(x-2)=1

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  1. log7 [(x-8)/(x-2)] = 1

    [(x-8)/(x-2)] = 7*1 = 7

    x - 8 = 7 x - 14

    6 x = 6
    x = 1

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