What is the summation of (n-3) from n=1 to n=5?
-2 -1 -0 + 1 + 2 = 0
That's the answer? That's how that problem is to be worked?
You could do it with an arithmetic series but that is only five simple terms.
Thank you!
x(1/2) - 5 sqrt 3x(1/4) + 18 = 0
To find the summation of (n-3) from n=1 to n=5, we can use the formula for the sum of an arithmetic series.
The formula for the sum of an arithmetic series is given by:
Sn = (n/2)(a₁ + an)
Where Sn is the sum of the series, n is the number of terms in the series, a₁ is the first term, and an is the last term.
In this case, we are given that the series starts from n=1 and ends at n=5, so the number of terms, n, is 5-1+1 = 5.
The first term, a₁, is (1-3) = -2, and the last term, an, is (5-3) = 2.
Now, we can substitute these values into the formula:
Sn = (5/2)(-2 + 2)
Simplifying further, we get:
Sn = (5/2)(0)
Since anything multiplied by zero is zero, the sum of this series is zero.
Therefore, the summation of (n-3) from n=1 to n=5 is 0.