What is the magnitude of the average acceleration of a skier who, starting from rest, reachers a speed of 8.0m/s when going down a slope for 5.0 s? how far does the skier travel in this time?
To find the magnitude of the average acceleration of the skier, you can use the equation:
average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity, u = 0 m/s (starting from rest)
Final velocity, v = 8.0 m/s
Time, t = 5.0 s
Substituting these values into the equation:
average acceleration = (8.0 m/s - 0 m/s) / 5.0 s
= 8.0 m/s / 5.0 s
= 1.6 m/s²
So, the magnitude of the average acceleration of the skier is 1.6 m/s².
To find how far the skier travels in this time, you can use the equation:
distance = (initial velocity + final velocity) / 2 * time
Substituting the values:
distance = (0 m/s + 8.0 m/s) / 2 * 5.0 s
= 8.0 m/s / 2 * 5.0 s
= 4.0 m/s * 5.0 s
= 20.0 m
Therefore, the skier travels a distance of 20.0 meters in this time.