factoring

5t^2-24t-5

  1. 👍
  2. 👎
  3. 👁
  1. how about
    (5t + 1)(t - 5)

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. calculus

    5. A particle moves along the x-axis in such a way that its position at time t is given by x=3t^4-16t^3+24t^2 for -5 ≤ t ≤ 5. a. Determine the velocity and acceleration of the particle at time t. b. At what values of t is the

  2. Math

    During softball practice, a softball pitcher throws a ball whose height can be modeled by the equation h = -16t^2 (

  3. Calculus

    The position of a particle moving on a horizontal line is given by s(t)=2t^3-15t^2+24t-5, where s is measured in feet and t in seconds. a: What is the initial position of the particle? b: What is the average velocity of the

  4. math

    At the beginning of a basketball game, the referee tosses the ball vertically into the air. Its height, h, in feet after t seconds is given by h(t) = -16t2 + 24t +5. During what time interval (to the nearest tenth of a second) is

  1. calculus

    Two runners, A and B run on a straight race track for 0

  2. Calculus

    The position function of a particle in rectilinear motion is given by s(t) s(t) = t^3 - 9t^2 + 24t + 1 for t ≥ 0. Find the position and acceleration of the particle at the instant the when the particle reverses direction.

  3. Precalc

    Find the continuous growth rate is Q=7000e^(0.24t)

  4. Calculus

    A particle moves on a vertical line. Its position, s, in metres at t seconds is given by s(t) = t^3 - 9t^2 + 24t, t>0/ I found the velocity and acceleration functions. s'(t) = 3t^2 - 18t + 24 s''(t) = 6t-18 b) When is the particle

  1. math

    on earth, in the absence of air, the rock in excersise 13 would reach a height of s=24t- 4.9t^2 meters in t seconds. How high would the rock go? (exercise 13:a rock thrown vertically upward from the surface of the moon at a

  2. Math-acceleration

    An object moves across a straight line so that after t seconds, is distance from its starting point is: D(t)=t^3 - 12t^2 + 100t + 12 meters. Find the acceleration of the object after 3 seconds. I believe acceleration is calculated

  3. math

    A rock is thrown vertically up from the ground with a velocity of 24 meters per second, and it reaches a height of 2+24t-4.9tsquare after t secounds. A. How many seconds after the rock is thrown will it reach its maximum height?

  4. math

    Given the position function s = 4t^3 − 24t^2 + 6t + 6. find s and v when a = 0 (Where v is the velocity and a is the acceleration.).

You can view more similar questions or ask a new question.