what is (x^2-8x+3) factored?
There are no rational factors of the expression.
Are you sure it is not a typo?
Anyway if it is for real, solve with quadratic
x = [ 8 +/- sqrt (64 -12) ]/2
= [8 + sqrt(52) ]/2
= [ 8 +/- 2 sqrt(13) ]/2
= 4 + sqrt 13
or
= 4 - sqrt 13
so
[ x - (4+sqrt 13)] [ x - (4-sqrt 13) ]
To factor the quadratic expression (x^2 - 8x + 3), we need to find two binomials whose product is equal to the original expression. Here's a step-by-step process to factor it:
Step 1: Identify the factors of the constant term (3): 1 and 3.
Step 2: Find the factors that add up to the coefficient of the middle term (-8). In this case, -1 and -3 are the factors that satisfy this condition because (-1) + (-3) = -8.
Step 3: Rewrite the quadratic expression by splitting the middle term (-8x) using the factors found in step 2.
(x^2 - 8x + 3) becomes:
x^2 - x - 3x + 3
Step 4: Group the terms and factor out the greatest common factor (GCF) from each group:
x(x - 1) - 3(x - 1)
Step 5: Notice that (x - 1) is common to both terms. Factor out the common binomial:
(x - 1)(x - 3)
Therefore, the factored form of (x^2 - 8x + 3) is (x - 1)(x - 3).