Solve this system 4x-12y=5 ,-x+3y=-1 by substitution
dude are you the same person as amy and taliyah? u guys are all posting the same type of questions.
no
To solve the system of equations using the substitution method, we'll solve one equation for one variable and substitute it into the other equation.
Let's solve the second equation, -x + 3y = -1, for x:
Add x to both sides:
3y = x - 1
Now, let's substitute this expression for x in the first equation, 4x - 12y = 5:
4(x - 1) - 12y = 5
4x - 4 - 12y = 5
4x - 12y = 9
So now we have a new system of equations:
4x - 12y = 9
-x + 3y = -1
Now, we can solve this new system of equations using the elimination method or substitution method. Let's use the elimination method here:
Multiply the second equation by 4 to make the coefficients of x match:
-4x + 12y = -4
Now, we can add the equations together to eliminate the x terms:
(4x - 12y) + (-4x + 12y) = 9 + (-4)
0 = 5
Uh-oh! We have reached an inconsistent equation where 0 does not equal 5. This means that the system of equations has no solution. There is no common point of intersection on the coordinate plane where both equations are satisfied simultaneously.