(4)/(x-3)+(2)/(3-x)
(4)/(x-3) + (2)/(-1)(-3+x)
i factor out a negative 1 from 3-x.
4/(x-3)+ 2/(x-3)
6/x-3
it suppose to be 2/x-3 how i get that?
But when you "factor out" the -1, it has to go somewhere, you can't just drop it , so ...
(4)/(x-3) + (2)/(-1)(-3+x)
= 4/(x-3) - 2/(-3+x)
= 2/(x-3)
remember what I showed you yesterday?
2/-1 = -2/1 = -(2/1)
thanks very much reiny :)
To find the simplified expression, let's go through the steps again:
Original expression: (4)/(x-3) + (2)/(3-x)
Step 1: Factor out a negative 1 from (3-x):
(4)/(x-3) + (2)/(-1)(-3+x)
Step 2: Simplify the expression:
(4)/(x-3) + (2)/(-1)(-3+x)
= (4)/(x-3) + (2)/(x-3)
Step 3: Since the denominators of both fractions are the same (x-3), you can combine the fractions:
= (4 + 2)/(x-3)
Step 4: Add the constants in the numerator:
= 6/(x-3)
So, the simplified expression is 6/(x-3), not 2/(x-3). Double-check your calculations and make sure you didn't make any errors along the way.