MO bisects <LMN,m<NMO=(6x+19)°,andm<LMO=(9x-14)°. Solve for x and find <LMN.
So the two angles would have to be equal
9x - 14 = 6x + 19
3x = 33
x = 11
angle LMO = 9x-14 = 99-14 = 85°
then angle LMN = 2*85 = 170°
Lm=5x-1. Kl=3x+2
i dont know sooooo
To solve for x and find the measure of <LMN, we can use the property that the sum of the angles in a triangle is 180 degrees.
Given that MO bisects <LMN, it means that m<NMO = m<LMO. Therefore, we can set up an equation using this information:
m<NMO = m<LMO
(6x + 19)° = (9x - 14)°
To solve for x, we can start by separating the x terms on one side and the constant terms on the other side:
6x + 19 = 9x - 14
Next, we can isolate the x terms by subtracting 6x from both sides of the equation:
19 = 3x - 14
To isolate the constant term on one side, we can add 14 to both sides:
33 = 3x
Finally, we can solve for x by dividing both sides by 3:
x = 11
Now that we have found the value of x, we can substitute it back into one of the given angles to find <LMN. Let's use m<NMO = (6x + 19)°:
m<NMO = (6 * 11 + 19)°
m<NMO = (66 + 19)°
m<NMO = 85°
Therefore, the measure of <LMN is 85 degrees.