Math

What is the sum of the first 200 odd numbers?

A rectangle has an area of 120 cm square we are trying to find possible perimeters. It's length and width are whole numbers. What are all the possibilities for the 2 numbers?

Give next two terms
3,4,7,11,18,29....
1,2,6,24,120....
77,49,36,18....

asked by Brittany snow
  1. Odd numbers: 1 , 3 , 5...

    200th od number = 399

    Now:

    1 + 399 = 400

    3 + 397 = 400

    5 + 395 = 400
    ....
    199 + 201 = 400

    100 * 400 = 40,000



    A = L * W = 120

    L = 120 / W

    120 = 2 * 2 * 2 * 3 * 5

    Ohe possibilities for the 2 numbers all numbers dividable with 2 3 and 5

    W = 120 , L = 120 / 120 = 1

    W = 60 , L = 2

    W = 30 , L = 4

    W = 15 , L = 8

    W = 10 , L = 12

    W = 8 , L = 15

    W = 6 , L = 20

    W = 4 , L = 30

    W = 3 , L = 40

    W = 2 , L = 60

    W = 1 , L = 120



    3,4,7,11,18,29....

    The previous two numbers make up the next number:

    3 + 4 = 7

    7 + 4 = 11

    11 + 7 = 18

    11 + 18 = 29


    Last two are:

    18 + 29 = 47

    and

    29 + 47 = 76



    3 ,4 , 7 , 11 , 18 , 29 , 47 , 76





    1 , 2 , 6 , 24 , 120..

    The multiplier increases by one each time:

    1 x 2 = 2

    2 x 3 = 6

    6 x 4 = 24

    24 x 5 = 120

    120 x 6 = 720

    720 x 7 = 5040


    1 , 2 , 6 , 24 , 120 , 720 , 5040





    77 , 49 , 36 , 18 ...



    77

    7 x 7 = 49

    4 x 9 = 36)

    3 x 6 = 18

    1 x 8 = 8)

    0 x 8 = 0


    77 , 49 , 36 , 18 , 8 , 0








    posted by Anonymous

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