15+2y-y^2/3y^2-16y+5
(5-y)(3+y)/(3y-1)(y-5)
i factor out a negative one from (5-y) to make it same like (y-5)
(-1)(-5+y)(3+y)/(3y-1)(y-5)
i cancel off y-5's. and i get
(-1)(3+y)/(3y-1)
but the real answer have to be 3+y/1-3y what i doing wrong?
Did you know that -3/4 = 3/-4 = -(3/4)
they are all the same
so look at your answer, which is correct
-1(3+y)/(3y-1)
= (3+y)/(-1(3y-1))
= (3+y)/(1-3y)
Sometimes it happens that you have an answer that looks different from the one in your text, but you may still be correct.
I would have marked your answer as correct to get full marks.
oh wow i had not know that thanks so much Reiny for telling and explaining to me :)
To understand where you made a mistake, let's go through the steps again:
Starting with the expression (5-y)(3+y) divided by (3y-1)(y-5):
We can rearrange (5-y) as (-1)(y-5), which is correct and maintains the same value of the expression.
So, we have (-1)(y-5)(3+y) divided by (3y-1)(y-5).
Now, we can cancel out the common factor of (y-5) in the numerator and denominator, which gives us:
(-1)(3+y) divided by (3y-1).
However, the final form of the expression should be (3+y) divided by (1-3y), not 3+y divided by (3y-1).
To obtain the correct expression, we need to multiply both the numerator and denominator of (-1)(3+y) divided by (3y-1) by -1, which gives us:
(-1)(-1)(3+y) divided by (3y-1)(-1).
Simplifying this further, we have:
(3+y) divided by (1-3y).
So, the correct answer is indeed (3+y)/(1-3y).