a 2.0 x 10^3 -kilogram car collides with a tree and is brought to rest in 0.50 seconds by an average force of 6.0 x 10^4 newtons. What is the magnitude on the impulse of the car durning this 0.50 -second interval?
3.0x10^4
30000 newtons per second
impulse= averageforce*time solve for force.
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Well, it seems the car had a not-so-friendly encounter with a tree. Let's calculate the magnitude of the impulse, shall we?
The impulse (J) can be calculated using the formula J = Δp, where Δp represents the change in momentum.
First, let's calculate the initial momentum (p_initial) of the car. We can find this by multiplying the mass of the car (m) by its initial velocity (v_initial). However, since the question doesn't provide the initial velocity, we'll have to use another approach.
Given that the car is brought to rest, we know its final momentum (p_final) is zero. Since momentum is conserved during the collision, we can equate the initial momentum to zero: p_initial = p_final.
Therefore, the change in momentum (Δp) is just equal to the initial momentum: Δp = p_initial.
Now we can calculate Δp using the average force (F_avg) and the duration of the collision (Δt) using the equation F_avg = Δp/Δt.
Plugging in the given values, we have 6.0 x 10^4 N = Δp/0.50 s.
Rearranging the equation, we find that Δp = 6.0 x 10^4 N * 0.50 s.
Calculating this, we get Δp = 3.0 x 10^4 kg·m/s.
So, the magnitude of the impulse for our car's unfortunate little tree collision is 3.0 x 10^4 kg·m/s.
Remember, next time, if you see a tree, it's always safer to give it a healthy distance!
To find the magnitude of the impulse, we can use the impulse-momentum relationship, which states that the impulse is equal to the change in momentum of an object. The formula for impulse is given by:
Impulse = Force * Time
In this case, the force is given as 6.0 x 10^4 newtons, and the time is given as 0.50 seconds.
Plugging in these values, we can calculate the impulse as follows:
Impulse = (6.0 x 10^4 N) * (0.50 s)
To multiply numbers written in scientific notation, we multiply the coefficient (the numbers before the multiplication sign) and add the exponents separately.
Impulse = 3.0 x 10^5 Ns
Therefore, the magnitude of the impulse of the car during the 0.50-second interval is 3.0 x 10^5 Newton-seconds.