solve for x in the following equations:

1) sin(arcsin x) = 1

2) 2arcsin x = 1

3) cos(arccos x) = 1/3

think of the definition of inverse trig functions

arcsin x is the angle Ø so that sinØ = x
so let arcsin x = Ø
then we have sin Ø = 1
so if sinØ = 1 and sinØ = x
x = 1
(we could see that right away since something like sin(arcsin 30°) = 30° )

2.
2 arcsin x = 1
arcsin x = 1/2
I know that sin π/6 = 1/2 or sin 30° = 1/2
so x = π/6 ( or 5π/6 , since the sine is also positive in quadrant II )

3. Just like in #1, x = 1/3

Okay thank you for the help on one and three. In my book for number two it says the answer is sin1/2 which is approx. 0.479. I'm not sure how that answer comes about.

My apologies

I solved as if it were 2sin x = 1

Don't know how I missed the "arc" since the whole question deals with it.

Anyway:
2 arcsinx = 1
arcsin x = 1/2
which by definition means
x = sin 1/2
so set your calculator to radians, and take sin .5
you will get .479...

Sure, let's solve each equation step-by-step.

1) sin(arcsin x) = 1

To solve this equation, we need to use the trigonometric identity arcsin(sin α) = α.

So, arcsin x = α.

Now let's rewrite the equation with α:

sin(α) = 1

Since sin(α) = 1 only when α = π/2, we have:

α = π/2

Now substitute back α with arcsin x:

arcsin x = π/2

To solve for x, take the sin of both sides:

x = sin(π/2)

The sine of π/2 is equal to 1, so x = 1.

Therefore, the solution to the equation is x = 1.

2) 2arcsin x = 1

We want to solve for x in this equation.

Divide both sides by 2:

arcsin x = 1/2

Now, using the same trigonometric identity arcsin(sin α) = α, we can rewrite the equation as:

x = sin(1/2)

Since the sine of 1/2 is a non-standard value, we can't simplify it further. The solution to this equation is x = sin(1/2).

3) cos(arccos x) = 1/3

First, using the trigonometric identity arccos(cos α) = α, we can rewrite the equation as:

x = cos(α)

Now, let's rewrite the equation with α:

cos(α) = 1/3

To solve for α, we take the inverse cosine (arccos) of both sides:

α = arccos(1/3)

Now substitute back α with arccos x:

arccos x = arccos(1/3)

To solve for x, we take the cosine of both sides:

x = cos(arccos(1/3))

The cosine of arccos(1/3) simplifies to 1/3, so x = 1/3.

Therefore, the solution to the equation is x = 1/3.