Sue and Sean are having a tug of war by pulling on opposite ends of a 1.43 kg rope. Sue pulls with a 46.47 N force. What is Sean's force if the rope accelerates toward Sue at 4.92 m/s2
Fn = F1-F2 = ma,
F1-46.47 = 1.43 * 4.92,
Solve for F1, Sean's force.
53.5N
To find Sean's force, we can use Newton's second law of motion, which states that force is equal to the mass multiplied by the acceleration. In this case, the force is towards Sue, so it will be a negative force.
Step 1: Convert the mass of the rope to kilograms.
Given: Mass of the rope = 1.43 kg
Step 2: Calculate Sue's force.
Given: Sue's force = 46.47 N
Step 3: Calculate the total force acting on the rope.
Total force = mass × acceleration
mass = 1.43 kg
acceleration = 4.92 m/s^2
Total force = 1.43 kg × 4.92 m/s^2
Step 4: Calculate Sean's force.
Given: Sean's force = Total force - Sue's force
Sean's force = (1.43 kg × 4.92 m/s^2) - 46.47 N
Now you can calculate the value for Sean's force.
To find Sean's force, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a). In this case, we have Sue's force, acceleration, and the mass of the rope.
First, let's calculate the mass of the rope. Given that the mass of the rope is 1.43 kg, we can use this value for the calculation.
Next, using Newton's second law equation, we can rearrange it to solve for Sean's force, F. The equation becomes F = m * a.
Substituting the known values into the equation:
F = 1.43 kg * 4.92 m/s^2
Calculating:
F = 7.004 kg⋅m/s^2
Therefore, Sean's force is approximately 7.004 N.