In a town election the winning candidate had 220 more votes that the loser. If 810 votes were cst in all, how many votes did each candidate receive?

Let x be the number of votes received by the winner. The loser got x-220.

x + x - 220 = 810
2x = 1030
Divide both sides of the equation by 2 for the answer.

515

To determine the number of votes each candidate received, we need to set up a system of equations based on the given information.

Let's assume the number of votes received by the loser is x.
Therefore, the number of votes received by the winning candidate is x + 220 (since the winning candidate had 220 more votes than the loser).

According to the problem, the total number of votes cast is 810. So, we have the equation:

x + (x + 220) = 810

To solve this equation and find the values of x and x + 220, we can simplify it:

2x + 220 = 810

Next, we subtract 220 from both sides of the equation:

2x = 810 - 220
2x = 590

Now, divide both sides of the equation by 2 to solve for x:

x = 590 / 2
x = 295

So, the loser received 295 votes.

To find the number of votes received by the winning candidate, we can substitute this value back into the equation:

x + 220 = 295 + 220
x + 220 = 515

Hence, the winning candidate received 515 votes.

Therefore, the loser received 295 votes and the winning candidate received 515 votes.