The sides of a rectangle are in the ratio 2:5. The perimeter of the rectangle is 70cm. What is the Width of the the rectangle.
Step 1: Let's assume the common ratio between the sides of the rectangle is 'x'.
Step 2: From the given information, we know that the length of the rectangle is 5x and the width is 2x.
Step 3: The perimeter of a rectangle is given by the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
Step 4: Substituting the values, we have 70 = 2(5x + 2x).
Step 5: Simplifying the equation, we get 70 = 2(7x).
Step 6: Dividing both sides by 2, we get 35 = 7x.
Step 7: Dividing both sides by 7, we get x = 5.
Step 8: Now that we have the value of x, we can find the width of the rectangle.
width = 2x = 2(5) = 10 cm.
Step 9: Therefore, the width of the rectangle is 10 cm.
To find the width of the rectangle, we need to determine the lengths of its sides.
Let's assume the sides of the rectangle are 2x and 5x, where x is a common factor.
The perimeter of a rectangle is given by the formula: Perimeter = 2 * (Length + Width).
In this case, the perimeter of the rectangle is 70 cm. Therefore, we can set up the following equation:
70 = 2 * (2x + 5x)
Simplifying the equation, we get:
70 = 2 * 7x
35 = 7x
x = 5
Now that we have the value of x, we can substitute it back into one of the side lengths to find the width. Let's substitute it into 2x:
Width = 2 * x
= 2 * 5
= 10 cm
Therefore, the width of the rectangle is 10 cm.
let the width be 2x
let the length be 5
2(2x+5x) = 70
7x = 35
x = 5
sides are 10 and 25