State the values for f(0) and f(-2)
show all your work
f(x){(2x-1 if x>1 ,-4 if -1¡Üx<1,2-x^2 if x<-1)
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http://www.jiskha.com/display.cgi?id=1325561243
I have to show all my work and I am unsure how to do that??
To find the values of f(0) and f(-2), we need to substitute the given values into the function and evaluate them step by step.
Let's start with f(0):
We can see that the function has three different cases for x: x > 1, -1 ≤ x < 1, and x < -1. Since we are dealing with f(0), which is x = 0, we can apply the relevant case for this value.
Case 1: x > 1
Since x = 0 is not greater than 1, we can eliminate this case from consideration.
Case 2: -1 ≤ x < 1
This is the only valid case for x = 0. We can substitute x = 0 into the corresponding expression, which is -4:
f(0) = -4
Now, let's move on to f(-2):
Using the same approach, we will find the appropriate case for x = -2.
Case 1: x > 1
Since x = -2 is not greater than 1, we can eliminate this case from consideration.
Case 2: -1 ≤ x < 1
Again, x = -2 falls outside of this range, so we discard this case as well.
Case 3: x < -1
Since x = -2 is less than -1, we will apply this case.
Substituting x = -2 into the corresponding expression, which is 2 - x^2:
f(-2) = 2 - (-2)^2
= 2 - 4
= -2
Therefore, the values of f(0) and f(-2) are:
f(0) = -4
f(-2) = -2