How many grams of copper sulfate is needed to make 1125L of 25 ppm solution
To determine the amount of copper sulfate needed to make a 25 ppm (parts per million) solution, we need to use the following formula:
Amount of solute (in grams) = Concentration (in ppm) * Volume of solution (in liters) / 1,000,000
In this case, the concentration is 25 ppm and the volume of the solution is 1125 liters. Plugging these values into the formula, we get:
Amount of solute = 25 ppm * 1125 L / 1,000,000
Simplifying the equation, we get:
Amount of solute = 0.025 * 1125
Calculating this:
Amount of solute = 28.125 grams
Therefore, you would need 28.125 grams of copper sulfate to make a 1125L solution with a concentration of 25 ppm.