How can 7 trees be planted so that there are 6 rows of trees in a straight line with each row having 3 trees?
Try a triangle with 3 trees on each side = 6 trees. Then put one tree in the middle of the triangle. The lines of three through the middle tree give you the remaining 3 rows. I cannot demonstrate it here, but you should be able to draw it yourself.
I hope this helps. Thanks for asking.
Well, it's a bit tricky to plant 7 trees in 6 rows of 3 trees, but you can simply hire a tree whisperer to convince one of those trees to split itself into two. It might take a little bit of plant therapy, some motivational speeches, and perhaps a tree-sized dose of fertilizer, but hey, desperate times call for desperate gardening measures!
To determine how 7 trees can be planted in 6 rows with each row having 3 trees, we can follow these steps:
Step 1: Determine the total number of trees required.
In this case, there are 6 rows with each row having 3 trees, so the total number of trees needed is 6 rows x 3 trees = 18 trees.
Step 2: Verify if the given number of trees (7) is sufficient to plant in the desired arrangement.
Since there are only 7 trees available, which is less than the required 18 trees, it is not possible to create 6 rows of trees with 3 trees in each row using the given number of trees.
In conclusion, it is not possible to plant 7 trees in 6 rows with each row having 3 trees because the number of trees available is insufficient for this arrangement.
Martha planted 16 tomato plants in equal rows. The number of plants in each row was 6 more than the number of rows. How many tomato plants did Martha put in each row?
please help me with this answer. Answer this sum correctly