An average song is 5,000 bytes (5B). ow many songs can an 4 gigabyte mp3 player store?
I'm not looking for an answer, but please explain how to solve this problem? I'm confused. There are many other problems like this on my homework and I don't know what to do.
giga means 10^9 a one with 9 zeros after it
5,000 = 5^10^5
so
we have
4 * 10^9 bytes on player
=========================
5 * 10^5 bytes per song
which is the same as
40 * 10^8 bytes on player
=========================
5 * 10^5 bytes per song
or
8 * 10^3 songs on a player
but 8*10^3 = 8,000
By the way K or kilo is the symbol for 1000 or 10^3
so 5,000 bytes is 5 KB, kilo bytes
5,000 = 5^10^3
so
we have
4 * 10^9 bytes on player
=========================
5 * 10^3 bytes per song
which is the same as
40 * 10^8 bytes on player
=========================
5 * 10^3 bytes per song
or
8 * 10^5 songs on a player
but 8*10^5 = 800,000
By the way K or kilo is the symbol for 1000 or 10^3
so 5,000 bytes is 5 KB, kilo bytes
To solve this problem, you need to follow these steps:
1. Convert gigabytes to bytes: The given mp3 player has a capacity of 4 gigabytes. To convert gigabytes to bytes, you need to multiply by the conversion factor. 1 gigabyte (GB) is equal to 1,073,741,824 bytes (B). So, 4 GB is equal to 4 * 1,073,741,824 = 4,294,967,296 bytes.
2. Calculate the number of songs: Since an average song is 5,000 bytes, you can divide the total capacity of the mp3 player by the size of each song. So, divide 4,294,967,296 (bytes) by 5,000 (bytes/song) to find the number of songs that can be stored.
3. Perform the division: Use a calculator or perform long division to find the answer. The calculation will be: 4,294,967,296 ÷ 5,000 = 858,993.4592.
4. Round the answer: Since songs cannot be stored fractionally, you'll need to round down the decimal to the nearest whole number. In this case, round down 858,993.4592 to 858,993. Thus, the mp3 player can store approximately 858,993 songs.
By following these steps, you should be able to solve similar problems where you are given a capacity and a size and asked to calculate the quantity.