A corner store sells two kinds of baked goods: cakes and pies. A cake costs $14 and a pie costs $8. In one day, the store sold 12 baked goods for a total of $144. How many cakes did they sell?

To solve this problem, let's use algebra.

Let's assume the number of cakes sold is represented by 'c' and the number of pies sold is represented by 'p'.

According to the problem, we know that a cake costs $14 and a pie costs $8. So we can set up two equations based on the number of cakes and pies sold:

c + p = 12 (since the store sold a total of 12 baked goods)
14c + 8p = 144 (since the total sales amounted to $144)

Now, we have a system of two equations with two variables. We can solve this system to find the values of 'c' and 'p'.

Let's solve the first equation for 'p':

p = 12 - c

Now substitute this value of 'p' in the second equation:

14c + 8(12 - c) = 144

Simplify the equation:

14c + 96 - 8c = 144
6c + 96 = 144

Subtract 96 from both sides:

6c = 48

Divide both sides by 6:

c = 8

So, the store sold 8 cakes.

Let's assume the number of cakes sold is represented by the variable "x".

Therefore, the number of pies sold can be represented by the expression (12 - x).

The cost of each cake is $14, so the total revenue from cake sales can be calculated as 14x.

Similarly, the cost of each pie is $8, so the total revenue from pie sales can be calculated as 8(12 - x).

Given that the total revenue from all the baked goods sold is $144, we can set up the equation:

14x + 8(12 - x) = 144

Now let's solve this equation step by step:

14x + 96 - 8x = 144

Combine like terms:

6x + 96 = 144

Subtract 96 from both sides of the equation to isolate the variable term:

6x = 48

Now, divide both sides of the equation by 6:

x = 8

Therefore, the store sold 8 cakes.

14 c + 8 p = 144

c + p = 12 so p = (12-c)

14 c + 8 (12-c) = 144
solve for c