earth

A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet.
Compared to the acceleration due to gravity near Earth’s surface, the acceleration due to gravity near the
surface of the planet is approximately

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asked by Anonymous
  1. On the planet that is NOT earth,
    Y (1/2)g'*t^2
    22 = (g'/2)*(3.0)^2
    so the value of the acceleration of gravity there is
    g' = 44/9 = 4.89 m/s^2

    The is just about half the value of g at the surface of the Earth (9.8 m/s^2)

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    posted by drwls

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