Calculus

write in the form of logA:
log2 + log12

3log5 + 2log3

1/4log81

log36 - log12

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  1. log 2 + log 12 = log (2*12) = log 24
    3log5 + 2log3 = log (5^3*3^2)= log 1125
    (1/4)log 81 = log 81^(1/4) = log 3

    You do the last one.
    Remember log a - log b = log a/b

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