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log_(1/4)⁡〖1/64〗+log_2⁡〖1/32〗-log_9⁡〖(75+x)〗-log_27⁡9=(-14)/3

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asked by Anonymous
  1. 1/4 ^3 = 1/64
    2^-5 = 1/32

    what's the base for log 279?
    I think you may have meant log_9 729 (9^3 = 729)

    Assuming that,

    3 - 5 - log_9(x+75) - 3 = -14/3
    log_9(x+75) = -1/3

    At this point, you can still solve it, but the answer is not as simple as it ought to be, judging from the problem. Check for further typos.

    posted by Steve

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