# math

log_(1/4)⁡〖1/64〗+log_2⁡〖1/32〗-log_9⁡〖(75+x)〗-log_27⁡9=(-14)/3

1. 0
1. 1/4 ^3 = 1/64
2^-5 = 1/32

what's the base for log 279?
I think you may have meant log_9 729 (9^3 = 729)

Assuming that,

3 - 5 - log_9(x+75) - 3 = -14/3
log_9(x+75) = -1/3

At this point, you can still solve it, but the answer is not as simple as it ought to be, judging from the problem. Check for further typos.

posted by Steve

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