An airplane of mass 2180 kg located 131 km north of U is

ying
272 km/hr in an easterly direction.
(a) What is the magnitude of the angular momentum (kg m2/s) with respect to U?
(b)what is the angular momentum with respect to U?

Angular momentum is M*V*R, since V is perpendicular to the R vector.

Convert V to m/s and R to meters before multiplying.

Except for including the direction of angular momentum, your two questions are the same. Get it from the cross product VxR and the right-hand rule

(a) Well, to find the magnitude of the angular momentum, we need to know the moment of inertia and the rotational speed. However, you've only provided the mass and the velocity of the airplane, so unfortunately we can't determine it. Looks like this question is trying to fly under the radar!

(b) As mentioned earlier, without the moment of inertia, we can't calculate the angular momentum with respect to U. It seems like this question is keeping us grounded in confusion. I guess we'll have to wait for more information to take off with the answer!

To find the magnitude of the angular momentum with respect to point U, we need to calculate the product of the mass of the airplane, its velocity vector, and the perpendicular distance from point U.

Given:
Mass of the airplane (m) = 2180 kg
Velocity of the airplane (v) = 272 km/hr = 272 * (1000/3600) m/s = 75.56 m/s
Distance of the airplane from point U (r) = 131 km = 131 * 1000 m = 131,000 m

(a) Magnitude of the angular momentum (L) = m * v * r

L = 2180 kg * 75.56 m/s * 131,000 m
L = 221,979,480 kg m^2/s

Therefore, the magnitude of the angular momentum with respect to U is 221,979,480 kg m^2/s.

(b) The angular momentum with respect to U will have a direction as well, which can be determined by the right-hand rule. Since the airplane is flying in an easterly direction (to the right), the angular momentum will be directed upwards (perpendicular to the plane's motion).

To find the magnitude of the angular momentum of the airplane with respect to point U, we need to determine the momentum and the moment of inertia.

(a) First, let's calculate the momentum.
The momentum (p) of an object is given by the product of its mass (m) and its velocity (v):
p = m * v

Given:
Mass of the airplane (m) = 2180 kg
Velocity of the airplane (v) = 272 km/hr

First, convert the velocity from km/hr to m/s:
1 km/hr = 1000/3600 m/s (conversion factor)
v = 272 * (1000/3600) m/s ≈ 75.6 m/s

Now, we can calculate the momentum:
p = 2180 kg * 75.6 m/s ≈ 165,048 kg m/s

(b) Next, let's determine the moment of inertia (I).
The moment of inertia (I) depends on the shape and distribution of mass of the object. Since the given question does not provide any information about the object's shape or size, we cannot calculate the exact moment of inertia. If you have additional information about the object's geometrical properties, we can use that to calculate the moment of inertia.

Therefore, we cannot solve part (b) without additional information.

In summary:
(a) The magnitude of the angular momentum of the airplane with respect to point U is approximately 165,048 kg m/s.
(b) We cannot determine the exact angular momentum without additional information about the object's geometrical properties.