1) Rectangle ABCD has a perimeter of 106 inches. If the width is 7 inches, what is the length?

2) If X=7 inches, Y=11 inches, Z=15 inches, and H=6 inches, what is the area of the triangle?

oh i forgot this


A. 88 square inches

B. 33 square inches

C. 21 square inches

D. 45 square inches

E. 94.5 square inches

2) Since you have the lengths of all three sides, you do not need the height, h, to get the area. If you use h, you need to know which side it is perpendicular to.

The half-perimeter is
s = (1/2)(a + b + c) = 16.5 inches.

The area is sqrt[s(s-a)*(s-b)*(s-c)] = __

It does not agree with any of your choices

1) To find the length of the rectangle, we need to use the formula for the perimeter of a rectangle:

Perimeter = 2 * (length + width)

In this case, we are given that the width is 7 inches and the perimeter is 106 inches. Plugging these values into the formula, we get:

106 = 2 * (length + 7)

We can simplify this equation by dividing both sides by 2:

53 = length + 7

To isolate the length, we subtract 7 from both sides:

length = 53 - 7

length = 46 inches

Therefore, the length of the rectangle is 46 inches.

2) To find the area of a triangle, we can use the formula:

Area = (1/2) * base * height

In this case, we are given the values X, Y, Z, and H. To calculate the area, we need to identify which values represent the base and the height.

The base of a triangle is usually denoted by the length of its bottom side, while the height is the perpendicular distance from the base to the opposite vertex.

Assuming that X is the base and H is the height, we can calculate the area using the given formula:

Area = (1/2) * X * H

Plugging in the values we have:

Area = (1/2) * 7 * 6

Area = (1/2) * 42

Area = 21 square inches

Therefore, the area of the triangle is 21 square inches.