3.
In the figure below, the perimeter of the parallelogram ABCD is (6a + 8b + 29) and the perimeter of the triangle ACD is (3a + 4b + 32). What is the length of AC
2(AD + DC) = 6a + 8b + 29
AD + DC + AC = 3a + 4b + 32
2(AD + DC + AC) = 6a + 8b + 64
2(AD + DC) + 2AC = 6a + 8b + 64
6a + 8b + 29 + 2AC = 6a + 8b + 64
29 + 2AC = 64
2AC = 35
AC = 53/2