Segment DF bisects angle EDG. Find FG.
segment EF is n+9
segment FG is 4n-6
Thank You :)!

Unless you know the distances DE and DG there's no way to be sure about EF and FG.

DF could be a very long line, DE could be short, and DG could be medium-length.

However, making the assumption that DE = EG, then we can make some headway.

In that case, EF = FG and so

n+9 = 4n-6
3n = 15
n=5

so EF = FG = 14

posted by Steve
2. THANK YOU! :)

posted by Zelda

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