A circular hatch in the hull of a submarine has a radius of 40.0 cm. The submarine is 850.0 m under water. If atmospheric pressure above the ocean is 1.01 x 105 Pa and the air pressure inside the submarine is 1.31x 105 Pa, what net force is exerted on the hatch? (ρsw = 1025 kg/m3)

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  1. Net force = (outside force) - (inside force)
    = (Area)*[(outside pressure) - (inside pressure)]

    Outside pressure = (psw*g*depth) + Po

    Area = pi*(0.40)^2 m*2

    Po = sea level atmospheric pressure = 1.01*10^5 Pa

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  2. pressure=100N/20M/S

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