A circular hatch in the hull of a submarine has a radius of 40.0 cm. The submarine is 850.0 m under water. If atmospheric pressure above the ocean is 1.01 x 105 Pa and the air pressure inside the submarine is 1.31x 105 Pa, what net force is exerted on the hatch? (ρsw = 1025 kg/m3)

Net force = (outside force) - (inside force)

= (Area)*[(outside pressure) - (inside pressure)]

Outside pressure = (psw*g*depth) + Po

Area = pi*(0.40)^2 m*2

Po = sea level atmospheric pressure = 1.01*10^5 Pa

pressure=100N/20M/S

To find the net force exerted on the hatch, we need to consider the pressure difference between the outside and the inside of the submarine. The net force will be the difference between the force exerted by the pressure outside the submarine and the force exerted by the pressure inside the submarine.

First, let's calculate the force exerted by the pressure outside the submarine. We can use the formula:

Force = Pressure x Area

The pressure outside the submarine is atmospheric pressure, which is 1.01 x 10^5 Pa. The area of the hatch can be calculated using the formula for the area of a circle:

Area = π x radius^2

Given that the radius of the hatch is 40.0 cm (or 0.4 m), we can substitute these values into the formula:

Area = π x (0.4)^2 = 0.50265 m^2 (approx)

Now we can calculate the force exerted by the pressure outside the submarine:

Force outside = Pressure outside x Area
= 1.01 x 10^5 Pa x 0.50265 m^2
= 5.084 x 10^4 N (approx)

Next, let's calculate the force exerted by the pressure inside the submarine. Similarly, we can use the formula:

Force = Pressure x Area

The pressure inside the submarine is given as 1.31 x 10^5 Pa, and the area of the hatch remains the same (0.50265 m^2). We can substitute these values into the formula:

Force inside = Pressure inside x Area
= 1.31 x 10^5 Pa x 0.50265 m^2
= 6.578 x 10^4 N (approx)

Finally, the net force exerted on the hatch is the difference between the force outside and the force inside the submarine:

Net force = Force outside - Force inside
= 5.084 x 10^4 N - 6.578 x 10^4 N
= -1.494 x 10^4 N (approx)

Therefore, the net force exerted on the hatch is approximately -1.494 x 10^4 N (in the opposite direction of the pressure difference).

To find the net force exerted on the hatch, we need to consider the pressure difference between the inside and outside of the submarine.

The net force is given by the equation:

F = P * A

where F is the net force, P is the pressure difference, and A is the area of the hatch.

First, let's calculate the pressure difference:

P = P_inside - P_outside

P_inside = 1.31 x 10^5 Pa (given)
P_outside = 1.01 x 10^5 Pa (given)

P = (1.31 x 10^5 Pa) - (1.01 x 10^5 Pa)
P = 0.3 x 10^5 Pa
P = 3 x 10^4 Pa

Now, let's calculate the area of the hatch:

A = π * r^2
A = π * (0.4 m)^2
A = 0.16π m^2

Next, we can substitute the values of pressure difference and area into the equation:

F = P * A
F = (3 x 10^4 Pa) * (0.16π m^2)
F = 4.8 x 10^3π N

Finally, we can approximate the value of π (pi) as 3.14:

F ≈ 4.8 x 10^3 * 3.14 N
F ≈ 15072 N

Therefore, the net force exerted on the hatch is approximately 15072 N.