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Calculus help!

(1) A toy truck travels at a rate of 0.5t ft/sec after t seconds of travel (so after 6 seconds the truck is traveling 3 ft/sec).

a) Graph the speed of the truck vs. time for 0<t<10.

b) Find the distance the truck has traveled in the first t seconds for 0<t<10. Call it T(t).

c) Find T'(5)

(2) A micorgram of Magnesium 28 contains approximately 3*10^16 atoms and this isotope has a half life of 21 hours.

a) Express the number of atoms of Magnesium 28 as a function of t, time in hours.

b) Approximately how many atoms of Magnesium 28 decay in the one second after 5 hours have passed? (Hint: what is the matematical relation for the decay as related to the amount?)

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anonymous

  1. “(1) A toy truck travels at a rate of 0.5t ft/sec after t seconds of travel (so after 6 seconds the truck is traveling 3 ft/sec). “

    why is it going suddenly slower, you said it was going at .5 ft/sec.

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    Reiny

  2. This is really a physics problem poorly expressed. I suspect it is accelerating.
    v = Vo + a t
    Vo = 0
    v = a t = .5 t

    v versus t is a straight line through the origin with slope 1/2

    T(t) = (1/2) a t^2
    = .25 t^2
    quadratic with slope zero at origin and going through (10, 25)

    I assume T' is the time derivative of T, or the speed
    T'(5) = v(5) = 2.5 ft/s

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    Damon

  4. starts with 3 * 10^16 atoms

    Meaning of half life
    for an exponential decay in time, some constant k
    mass = initial mass e^-kt
    or
    M = Mo e^-kt
    now when is m = .5 Mo ?

    .5 = e^-k T where T is half life
    ln .5 = -k T
    ln .5 = -k (21 hr)
    -.6931 = - 21*k
    k = .033

    So for this stuff
    M = Mo e^-.033 t where t is in hours
    here Mo is 3*10^16 so make your graph

    Part b
    we want d M/dt in seconds when t = 5 hr

    dM / dt = -(3*10^16).033 e^- (.033*5)
    you can do that
    then that is number lost per hour
    divide by 3600 to get per second.

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    Damon

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